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n^2-2000n+510000=0
a = 1; b = -2000; c = +510000;
Δ = b2-4ac
Δ = -20002-4·1·510000
Δ = 1960000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1960000}=1400$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2000)-1400}{2*1}=\frac{600}{2} =300 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2000)+1400}{2*1}=\frac{3400}{2} =1700 $
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